Calendar
1 January 1 AD Monday was
Monday is the first day of the week .
Normal year - in the year 365 ( 365 ) days ( 52 weeks and 1 day ) are called normal year .
Leap year , leap year , leap year , leap Year = the year of 366 days ( 52 weeks and 2 days ) are . Leap Year will be the year in which he will go full part 4 . And part 400 full century - the century leap year shall be deemed to be completed .
Odd day - full weeks additional days at a time is called the odd day . The number of days in the year anomalous surface- odd days in a leap year and that number is two .
The normal year wise / day starts ends on the same day
Leap year that started from the day ends the next day .
February has 28 days in a normal year
February has 29 days in leap year .
The month is 29 days starts from the day he ends the same day .
The month is 30 days starts from the day he ends the next day .
The month is 31 days starts from the day he ends two days later .
Determining the number of odd days : -
Normal number of days in a year - 365/7 = 52 ( remainder - 1 ) This is a day odd day .
Leap year - 365/7 = 52 ( left 2) The two-day odd day.
Determining the number of odd days in a century -
100 years leap year will have 24 because 99 divided by 4 to get 24 100 is not part of the 400 . Because the 100 century , therefore, has to be part of it, 400 .
100 years = 76 ordinary years + 24 leap years = (76x52 days +76 days ) + (24x52 +24 x2 day of the week )
+ = 76 x 52 weeks ( 10 weeks + 6 days ) + 24 x 52 + weeks ( 6 weeks + 6 days )
+ Week + 12 days = 5216 days = 5216 ( 1 week + 5 hours )
= 5217 week + 5 hours
The number of odd days in 100 years - 5
The number of odd days in 200 years - 2X5 days - 10 days = 1 week + 3 days = 3
The number of odd days in 300 years - 3X5 DAY-15 DAY = 2 WEEK + 1 DAY = 1
The number of odd days in 400 years - 4X5 +1 - 21 DAY = 3 WEEK = 0
( 400 th year will be a leap year , so 1 is added )
Number of consecutive years in 400 years Leap 4x24 +01 = 97 [400 of 400 runs . Therefore added 1 ]
Similarly, 800 , 1200 , 1600, 2400 years have 0 odd number of days .
Months of the calendar year is the same in general .
January-October
February - March to November
April-July
September to December
The same month, leap year
January - April - July
February August -
March to November
September to December
Date and day of any given day To find another date -
Now is the day in question beyond the odd day will count the same day . How odd number of days over which it can be known .
Odd number of days and hours
0 - Sunday
1 - Monday
2 - Tuesday
3 - Wednesday
4 - Thursday
5 - Friday
6 - Saturday
The number of days remaining in months
There are many days in the month divided by 7 and let them do the rest avoiding the odd day.
January - 31/7 = 4week +3 day = 3
February -0.1
March -3
April -2
May -3
June -2
July -3
August -3
September -2
October -3
November -2
December -3
Q.1 - 10 April 2003 Monday, July 20 to do so would be wise .
We can solve this in two ways .
First Method : -
April + May + June + July
20 +31 +30 +20 = 101
Now we have to take extra days to get part 7
101/7 = 14 remainder 3
So you can add three days Monday to Thursday
Second method: -
April + May + June + July
2 +3 +2 +3 = 10
10/7 = 1 remainder 3
Hence : Monday to Thursday for three days and then will give added .
By the same method you get started right now .
If tomorrow is Saturday after two days , then two days before yesterday was what day of the week . [PCE -2007]
(a) Friday
(b) Thursday
(c) Saturday
(d) Monday (A)
Fri , Sat , Sun , Mon , * Tue * Wed , Thu , Fri , Wed.
If tomorrow is Friday after two days , then two days before yesterday was what day of the week . [PCE -2007]
(a) Friday
(b) Thursday
(c) Saturday
(d) Monday (b)
Thu , Fri , Sat , Sun , * M * Tue , Wed , Thu , Fri
Abhishek's birthday on the third Saturday of the month , the third day of the month is Monday . Which of the following will have on the date of Abhishek's birthday . [PCE -2007]
(a) 14
(b) 15
(c) 16
(d) 17 (b)
1 (Sat - first ), 2 ( S ) 3 ( Monday - was in question ) so 8 Saturday ( second ) , 8 +7 ??= 15 ( Saturday - third )
Monday the 5th of March, two days later, which is seen on the first day of the next month . [PCE -2007]
(a) Monday
(b) Tuesday
(c) Wednesday
(d) Thursday (b)
In 2005, Independence Day was celebrated on Monday . What day was celebrated in 2006 ? [PCE -2009]
(a) Monday
(b) Tuesday
(c) Skrwar
(d) Thursday (b)
On the January 30, 2003 What day is Thursday would then 2 March 2003 . [PCE -2011]
(a) Tuesday
(b) Saturday
(c) Thursday
(d) Sunday (d)
Sunday 23rd of any month , then what day will have two weeks and four days ago . [PCE -2013]
(a) Wednesday
(b) Thursday
(c) Monday
(d) Tuesday (A)
Sunday is the first day of a normal year would be the first day of the next year . [PCE - 2013]
(a) Monday
(b) Tuesday
(c) Wednesday
(d) Saturday (A)
Iin hindi click hear - Reasoning - Calendar
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